Today, we will see a simple Python 3 program to check Armstrong’s number. In case you missed our previous Python 3 blog, do check it out where I have created a simple Python calculator.
To understand this example, you should know the following Python programming concepts.
- Variables and Datatypes
- If-else statement
- While loop
You can also refer these best Python books for beginners to add more resources in your learning path.
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Must Read: How To Send Email Using Python With Attachments.
Python 3 Program to Check Armstrong Number
Simply put, a number is called as an Armstrong number when the number is equal to the sum of its digits raised to the total number of digits.
For example, let’s check if 153 is an Armstrong number or not. Here, the total number of digits is 3. Therefore, we will calculate the cubes of individual figures and see if their sum is equal to the number itself.
Cube of 1 = 1
Cube of 5 = 125
Cube of 3 = 27
Cube of 1 + Cube of 5 + Cube of 3 = 153 (the number itself). Hence, 153 is an Armstrong number.
In our Python code, we have to replicate the same logic to check whether the given number is Armstrong number or not.
Step 1: Get the input from the user to check.
Step 2: Store the input in a temporary variable.
Step 3: Create a variable to store the sum and initiate it with zero.
Step 4: Now, find the length of the input number by using the len() function and store it in a variable.
Step 5: Use the While loop to find the sum of individual digits raised to the length of the number.
Step 6: Use the if-else statement to check if the sum is equal to the actual or not. If it is equal, then the user will see the message that the entered number is Armstrong; otherwise, the number is not an Armstrong number.
num = int(input("Enter the number:")) temp = num sum = 0 power = len(str(num)) while temp > 0: digit = temp % 10 sum = sum + digit ** power temp = temp // 10 if num == sum: print("The entered number is Armstrong number.") else: print("Entered number is not a armstrong number")
Try it yourself:
Enter the number: 153
The entered number is Armstrong number.
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